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Two mole of argon are mixed with one mole of hydrogen, then \mathrm{C_{p} / C_{v}} for the mixture is nearly

Option: 1

1.2


Option: 2

1.3


Option: 3

 1.4


Option: 4

1.5


Answers (1)

best_answer

Average degree of freedom

\mathrm{f_{a v}=\frac{2 \times 3+1 \times 5}{2+3}=\frac{11}{5}}
\mathrm{ \gamma_{\text {mix }}=1+\frac{1}{f_{\text {av }}}=1+\frac{5}{11}=\frac{16}{11}=1.4}

Hence, C is correct Answer.

Posted by

Gautam harsolia

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