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  • Two resistors <img alt="\mathrm{R}_{1}=(4 \pm 0.8) \Omega$ and $\mathrm{R}_{2}=(4 \pm 0.4) \Omega" src="https://entrancecorner.codecogs.com/gif.latex?%5Cmathrm%7BR%7D_%7B1%7D%3D%284%20%5Cpm%200.8%29%20%5COmega%24%20and%20%24%5Cmathrm%7BR%7D_%7B2%7D%3D%284

Two resistors \mathrm{R}_{1}=(4 \pm 0.8) \Omega$ and $\mathrm{R}_{2}=(4 \pm 0.4) \Omega are connected in parallel. The equivalent resistance of their parallel combination will be :
    
Option: 1 (4 \pm 0.4) \Omega
Option: 2 (2 \pm 0.4) \Omega
Option: 3 (4 \pm 0.3) \Omega
Option: 4 (2 \pm 0.3) \Omega

Answers (1)

best_answer


\frac{1}{R_{eq}}= \frac{1}{R_{1}}+\frac{1}{R_{2}}
\frac{\Delta R_{eq}}{R_{eq^{2}}}= \frac{\Delta R_{1}}{R_{1}^{2}}+\frac{\Delta R_{2}}{R_{2}^{2}}
R_{eq}= \frac{R_{1}R_{2}}{R_{1}+R_{2}}= 2
\frac{\Delta R_{eq}}{\left ( 2 \right )^{2}}= \frac{0\cdot 8}{16}+\frac{0\cdot 4}{16}
               = \left ( 0\cdot 2 \right )+\left ( 0\cdot 1 \right )
\Delta R_{eq}= 0\cdot 3
R_{eq}\pm \Delta R_{eq}= \left ( 2\pm 0\cdot 3 \right )\Omega
The correct option is (4) 

Posted by

vishal kumar

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