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  • Which option best describes the bond angle present in <img alt="\mathrm{H}_2 \mathrm{Se} \text{ and } \mathrm{PH}_3" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BH%7D_2%20%5Cmat

Which option best describes the bond angle present in \mathrm{H}_2 \mathrm{Se} \text{ and } \mathrm{PH}_3?
 

Option: 1

between 109^{\circ} \text{and } 120^{\circ}
 


Option: 2

greater than 120^{\circ}
 


Option: 3

less than in \mathrm{H}_2 \mathrm{S} but not less than the bond angle in \mathrm{H}_2 \mathrm{Te}


Option: 4

less than the bond angle in \mathrm{H}_2 \text{Te}


Answers (1)

best_answer

According to Drago's rule when atoms of group 14,15 and 16 are attached to atoms having electronegativity less than 2.5, then it has the lone pair of \mathrm{e^{-}} pure s-orbitals and bond angles are close to 90^{\circ}. Down the group, bond angle of hydrides decreases.

\\\mathrm{\angle HXH}:\mathrm{\mathrm{H}_2 \mathrm{O}>\: \: \mathrm{H}_2 \mathrm{~S}>\: \: \mathrm{H}_2 \mathrm{Se}>\: \: \mathrm{H_{2}}{\mathrm{Te}}}\\

                     104.5^{\circ}\: \: \: \: \: 92^{\circ}\: \: \: \: \: \: \: \: \: \: \: 91^{\circ}\: \: \: \: \: \: \:\: \: \: 89.5^{\circ}

\mathrm{PH_{3}}:(93^{\circ})

Posted by

Rakesh

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