Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A charge particle of mass m and charge q initally at rest is released in an electric field of magnitude E. Kinetic energy after time t will be :Option: 1</strong

A charge particle of mass m and charge q initally at rest is released in an electric field of magnitude E. Kinetic energy after time t will be :

Option: 1

\frac{2 E^2 t^2}{m z}


Option: 2

\frac{E^2 q^2 t^2}{2 m}


Option: 3

\frac{E q^2 m}{2 t^2}


Option: 4

\frac{E q m}{2 t}


Answers (1)

best_answer

Use newton's equation of motion -

\mathrm{\begin{array}{ll} v=u+a t & F=m a \\ v=0+a t, & f=q E \\ k=a t-(2) & m a=q E \\ a=\frac{q E}{m} \end{array} }
put the value of a in equation (1) we get -

\mathrm{v=\frac{q E t}{m} }
Kinetic energy \mathrm{K=\frac{1}{2} m \cdot u^2 }
\mathrm{\begin{aligned} & =\frac{1}{2} m \cdot\left(\frac{q E t}{m}\right)^2 \\ & =\frac{1}{2} m \cdot \frac{q^2 E^2 t^2}{m^2} \\ k \cdot E \cdot & =\frac{q^2 E^2 t^2}{2 m} \text { Ans } \end{aligned} }

Posted by

Sanket Gandhi

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

MCC NEET UG 2024 Counselling: Special round schedule out; choice filling begins from November 20
anam-khan

Rajasthan NEET UG counselling board cancels MBBS admissions of 100 students at PMCH
anam-khan

100 MBBS students’ fate uncertain as HC reverses ruling on extra seats at Rajasthan private medical college

Latest Question