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  • 0.5 F of electricity is passed through 500 mL of copper sulphate solution. The amount of copper (in g) which can be deposited will be:Option: 1

0.5 F of electricity is passed through 500 mL of copper sulphate solution. The amount of copper (in g) which can be deposited will be:

Option: 1

31.75


Option: 2

15.8


Option: 3

47.4


Option: 4

63.5


Answers (1)

best_answer

\mathrm{Cu}^{2+}+2 e^{-} \longrightarrow \mathrm{Cu}

\begin{array}{l}{2 \mathrm{\: F}=1 \mathrm{\: mol} \text { of } \mathrm{Cu}=63.5 \mathrm{\: g\: of} \mathrm{\: Cu}} \\\\ {0.5 \mathrm{\: F}=\frac{63.5}{2} \times 0.5=15.8 \mathrm{g}}\end{array}

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Anam Khan

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