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A uniform magnetic field of intensity\mathrm{B=B_0 \sin (\omega t)}directed into the plane of the paper exists in the cylindrical region of radius r. A loop of resistance R = 5\Omega is folded in the form of an equilateral triangle of side length 2r is placed as shown in the figure. The maximum potential drop in the wire AB is

Option: 1

\mathrm{\frac{\pi r^2 B_0 \omega}{6} volt}


Option: 2

\mathrm{\frac{\pi \mathrm{r}^2 \mathrm{~B}_0 \omega}{3} volt}


Option: 3

\mathrm{\frac{\pi r^2 B_0 \omega}{2} volt}


Option: 4

\mathrm{\pi r^2 B_0 \omega}


Answers (1)

best_answer

Potential drop is only across wire AB
\mathrm{\begin{aligned} & \phi=\mathrm{B}_0 \sin (\omega \mathrm{t}) \cdot\left(\frac{\pi \mathrm{r}^2}{6}\right) \\ & \varepsilon=\left|\frac{-\mathrm{d} \phi}{\mathrm{dt}}\right|=\frac{\mathrm{B}_0 \omega \pi \mathrm{r}^2}{6} . \end{aligned}}

Posted by

Gautam harsolia

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