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An 80 Ω galvanometer deflects full-scale for a potential of 20 mV. A voltmeter deflecting full-scale of 5 V is to be made using this galvanometer. We must connect

Option: 1

A resistance of 19.92 kΩ parallel to the galvanometer


Option: 2

A resistance of 19.92 kΩ in series with the galvanometer


Option: 3

A resistance of 20 kΩ parallel to the galvanometer


Option: 4

A resistance of 20 kΩ in series with the galvanometer


Answers (1)

best_answer

The current through the galvanometer producing full scale deflection is

\mathrm{I=\frac{V}{R}=\frac{20 \times 10^{-3}}{80}=2.5 \times 10^{-4} \mathrm{~A} }
To convert the galvanometer into a voltmeter, a high resistance is connected in series with the galvanometer
\mathrm{ \therefore 5 \mathrm{~V}=\left(2.5 \times 10^{-4}\right)(R+80) \text { or } R=19.92 \mathrm{k} \Omega }

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jitender.kumar

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