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An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted, illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, then the value of n is

Option: 1

5


Option: 2

2


Option: 3

3


Option: 4

4


Answers (1)

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\begin{array}{l} E = KE _{\max }+ W \\ \\ eV _{0}+ W =10+2.75 \\ \\ E =12.75 eV \end{array}

The difference of 4 and 1 energy level is 12.75 eV. So, the higher energy level is 4 to the ground and excited state is n =3

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Divya Prakash Singh

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