If the rate constant for a first order reaction is k, the time (t) required for the completion of 99% of the reaction is given by:

  • Option 1)

    t = 0.693/k

  • Option 2)

    t = 6.909/k

  • Option 3)

    t = 4.606/k

  • Option 4)

    t = 2.303/k

 

Answers (3)

Option 3

For first order reaction,

    t_{\frac{1}{2}} = \frac{2.303}{k}\log_{10}\frac{a}{a-x}

a = 100\%\;\;\;\;x=99\%

        a - x= 1\%

t_{\frac{1}{2}} = \frac{2.303}{k}\log_{10}\frac{100}{1} = \frac{2.303}{k}\log_{10}10^2

t_{\frac{1}{2}} = \frac{2.303}{k}\times 2 = \frac{4.606}{k}


Option 1)

t = 0.693/k

Option 2)

t = 6.909/k

Option 3)

t = 4.606/k

Option 4)

t = 2.303/k

t = 2.303/k

Option 4

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