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My_Snapshot_11.jpg 10 mL of gaseous hydrocarbon on combustion give 40 mL of C02(g) and 50 mL of H20 (vap.). The hydrocarbon is -

Answers (1)

Question 60-

 

first solution is -

10 mL of gaseous hydrocarbon on combustion gives 40 mL of CO2


The number of C atoms in the formula unit is 40/10×1=4

and
10 mL of gaseous hydrocarbon on combustion gives 50 mL of H2O
50/10×2 =10
 The hydrocarbon is C4H10

 

Second solution is:-

the ratio of volumes is 
10 : 40 : 50 
1 : 4 : 5 

all the Carbon from the hydrocarbon is in the CO2 
10 ml of hydrocarbon produces 40 ml CO2, 
1 : 4 ratio 
So 1 mole hydrocarbon has 4 moles Carbon 

All the H ends up in the water 
10 ml hydrocarbon produces 50 ml water, 
1 : 5 ratio, 
but also each water has 2 H atoms 
So 1 mole hydrocarbon has 10 moles Hydrogen 

which gives 
C4H10 

You can balance an equation for combustion of C4H10 to check the answer 

C4H10 + 13/2 O2 --> 4CO2 + 5H2O

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Ankit

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