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  • Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations(NEET 2018)

  1. a) 60 ml \frac{M}{10} HCl + 40 ml \frac{M}{10} NaOH
  2. B) 55 ml\frac{M}{10} HCl + 45 ml \frac{M}{10} NaOH
  3. c) 75 ml \frac{M}{5} HCl + 25 ml \frac{M}{5} NaOH
  4. d) 100 ml \frac{M}{10}  HCl + 100 ml \frac{M}{10} NaOH

pH of which one of them will be equal to 1

  1. a
  2. b
  3. c
  4. d

Answers (1)

The p(H) scale -

Hydronium ion concentration in molarity is more conveniently expressed on a logarithmic scale known as p(H) scale.

- wherein

The p(H) of a solution is defined as negative logarithm to base 10 of the activity of hydrogen ion

P(H)=-log[H^{+}]

 

 As N1V1 > N2V2 so acid left at the end of the reaction

N_{mixture} = [H]^{+} =\frac{N_{1}V_{1} - N_{2}V_{2}}{V_{1} + V_{2}} = \frac{\frac{1}{5}X75 - \frac{1}{5}X25 }{75+25} = \frac{1}{10} = 10^{-1}

pH = -log10^{-1} = 1

 

So acid is left at the end of the reaction

Option 4)

c

This is correct.

Posted by

Ankit Dutt

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