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  • For photoelectric emission from certain metal the cutoff frequency is . If radiation of frequency 2 <im

For photoelectric emission from certain metal the cutoff frequency is \nu. If radiation of frequency 2 \nu impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass):

Option: 1

2\sqrt{h\nu / \text{m}}


Option: 2

\sqrt{h\nu / (2\text{m})}


Option: 3

\sqrt{h\nu / \text{m}}


Option: 4

\sqrt{2h\nu / \text{m}}


Answers (1)

best_answer

\\ As \ \frac{1}{2} mv _{ max }^{2}= hv \\ \Rightarrow v_{\max }^{2}=\frac{2 h v}{m} \\ therefore, \\ v_{m a x}=\sqrt{\frac{2 h v}{m}} \\As \frac{1}{2} m v_{\max }^{2}=h v \\ \Rightarrow v_{\max }^{2}=\frac{2 h v}{m} \\ therefore, v_{m a x}=\sqrt{\frac{2 h v}{m}}

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