Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • For photoelectric emission from certain metal the cutoff frequency is . If radiation of frequency 2 <im

For photoelectric emission from certain metal the cutoff frequency is \nu. If radiation of frequency 2 \nu impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass):

Option: 1

2\sqrt{h\nu / \text{m}}


Option: 2

\sqrt{h\nu / (2\text{m})}


Option: 3

\sqrt{h\nu / \text{m}}


Option: 4

\sqrt{2h\nu / \text{m}}


Answers (1)

best_answer

\\ As \ \frac{1}{2} mv _{ max }^{2}= hv \\ \Rightarrow v_{\max }^{2}=\frac{2 h v}{m} \\ therefore, \\ v_{m a x}=\sqrt{\frac{2 h v}{m}} \\As \frac{1}{2} m v_{\max }^{2}=h v \\ \Rightarrow v_{\max }^{2}=\frac{2 h v}{m} \\ therefore, v_{m a x}=\sqrt{\frac{2 h v}{m}}

Posted by

Info Expert 30

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Medical courses after Class 12th without NEET 2025; course-wise eligibility, career prospectus
anam-khan

Aakash launches free rapid revision course for NEET; paid crash course for JEE Advanced
anam-khan

NEET 2025 exam passing marks out of 720 for MBBS aspirants

Latest Question