If there are 999 bases in RNA that codes for a protein with 333 amino acids, and the base at position 901 is deleted such that the length of the RNA becomes 998 bases, how many codons will be altered?
1
11
33
333
999 bases in RNA codes for a protein with 333 amino acids correct that is
900 + 99 bases or you can say 900 + 901 + 902 and so on..... and 300 + 33 codons..
If base at 901 position is deleted then first 900 bases will be normal while bases after 901th base will be altered that is 99 bases will be altered.
3 bases stand for 1 codon, that is 99 bases are coded by 33 codons will be altered due to the deletion of one base at 901 position.
Hence, the correct answer is (c).