Oxidation of succinate ion produces ethylene and carbon dioxide gases. On passing 0.2 Faraday electricity through an aqueous solution of potassium succinate, the total volume of gases (at both cathode and anode) at STP (1 atm and 273 K) is :
2.24 L
4.48 L
6.72 L
8.96 L
The chemical equation we have:
Now, equivalents of (C2H4 + CO2 + H2) = 0.2 + 0.2 + 0.2
= 0.6
Now, total number of moles of gases = 0.2/2 + 0.2/1 + 0.2/2 = 0.4
Now, from ideal gas equation, we have:
pV = nRT
Therefore, V = (0.4 x 0.0821 x 273)/1
V = 8.96L
Therefore, Option (4) is correct