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  • Oxidation states of the metal in the minerals cuprite and tenorite, respectively are:Option: 1 I in cuprite and I, II in tenorite

Oxidation states of the metal in the minerals cuprite and tenorite, respectively are:

Option: 1

I in cuprite and I, II in tenorite


Option: 2

I in cuprite and II in tenorite


Option: 3

II in cuprite and I, II in tenorite


Option: 4

II in cuprite and II in tenorite


Answers (1)

best_answer

Cuprite is a mineral that consists of copper(I) oxide \left(\mathrm{Cu}_2 \mathrm{O}\right). In cuprite, the oxidation state of the copper ion (\mathrm{Cu})  is +1 . Therefore, the correct oxidation state of the metal in cuprite is I.

Tenorite, on the other hand, is a mineral that consists of copper(II) oxide (CuO). In tenorite, the oxidation state of the copper ion (\mathrm{Cu}) is +2 . Therefore, the correct oxidation state of the metal in tenorite is II.

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