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Which one is the wrong statement?

  • Option 1)

    de-Broglie's wavelength is given by \lambda = \frac{\text{h}} {{\text{m}\upsilon }},  where m = mass of the particle, \upsilon = group velocity of the particle.

     

  • Option 2)

    The uncertainty principle is \Delta \text{E} \times \Delta \text{t} \geqslant {\raise0.7ex\hbox{\text{h}} \!\mathord{\left/ {\vphantom {\text{h} {4\pi }}}\right.\kern-\nulldelimiterspace} \!\lower0.7ex\hbox{{4\pi }}}.

  • Option 3)

    Half-filled and fully filled orbitals have greater stability due to greater exchange energy, greater symmetry and more balanced arrangement.

  • Option 4)

    The energy of 2s orbital is less than the energy of 2p orbital in case of Hydrogen like atoms.

 

Answers (1)

best_answer

As we learnt in

Principal Quantum Number -

The principal quantum number determines the size and to large extent the energy of the orbital.

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 For hydrogen like atom, the energy of 2s orbital is same as energy of 2p orbital.


Option 1)

de-Broglie's wavelength is given by \lambda = \frac{\text{h}} {{\text{m}\upsilon }},  where m = mass of the particle, \upsilon = group velocity of the particle.

 

Incorrect

Option 2)

The uncertainty principle is \Delta \text{E} \times \Delta \text{t} \geqslant {\raise0.7ex\hbox{$\text{h}$} \!\mathord{\left/ {\vphantom {\text{h} {4\pi }}}\right.\kern-\nulldelimiterspace} \!\lower0.7ex\hbox{${4\pi }$}}.

Incorrect

Option 3)

Half-filled and fully filled orbitals have greater stability due to greater exchange energy, greater symmetry and more balanced arrangement.

Incorrect

Option 4)

The energy of 2s orbital is less than the energy of 2p orbital in case of Hydrogen like atoms.

Correct

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Aadil

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