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The coefficient of mutual inductance of the two coils is 0.5 H. If the current is increased from 2 to 3 A in 0.01 sec. in one of them, then the induced e.m.f. in the second coil is :

Option: 1

25 V


Option: 2

50 V


Option: 3

75 V


Option: 4

100 V


Answers (1)

best_answer

\mathrm{\text { Induced emf }=\mathrm{M} \frac{\mathrm{di}}{\mathrm{dt}}}

\mathrm{=0.5 \frac{3-2}{0.01}=50 \mathrm{~V}}

Posted by

HARSH KANKARIA

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