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  • The frequency of incident light falling on a photo sensitive plate is doubled, then maximum kinetic energy of the emitted photoelectrons will become –Optio

The frequency of incident light falling on a photo sensitive plate is doubled, then maximum kinetic energy of the emitted photoelectrons will become –

Option: 1

2 times of the earlier value


Option: 2

More than 2 times of the earlier value


Option: 3

Less than 2 times of the earlier value


Option: 4

Unchanged


Answers (1)

best_answer

\begin{aligned} & K E_{\max }=\mathrm{h}\left(v-v_0\right) \\ & \frac{K E_{\max }^{\prime}}{K E_{\max }}=\frac{\mathrm{h}\left(2 v-v_0\right)}{\mathrm{h}\left(v-v_0\right)}>2 \end{aligned}

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Deependra Verma

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