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  • The order of energy absorbed which is responsible for the color of complexes <img alt="\mathrm{(A)} \left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}(\mathrm{en})_{2}\right]^{2+}"

The order of energy absorbed which is responsible for the color of complexes
\mathrm{(A)} \left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}(\mathrm{en})_{2}\right]^{2+}

\mathrm{(B)}\mathrm{[Ni(H_{2}O)_{4}(en)]^{2+}}\, \mathrm{and}

\mathrm{(C)}\mathrm{[Ni(en)_{3}]^{2+}} is

Option: 1

(C)>(B)>(A)


Option: 2

(C)>(A)>(B)


Option: 3

(B)>(A)>(C)


Option: 4

(A)>(B)>(C)


Answers (1)

best_answer

As we have learnt,

Energy absorbed by complexes depends upon the sitting energy.

Metal ion remaining save, splitting is greater for strong field chelating ligands.

\therefore Order of sitting in given complexes is

\mathrm{\left [ Ni(en)_{3} \right ]^{2+}}>\mathrm{\left [ Ni(H_{2}O)_{2}en_{2} \right ]^{2+}}> \mathrm{\left [ Ni(H_{2})_{4}en \right ]^{2+}}

(C)                            (A)                                 (B)

hence correct option is 2.

Posted by

vishal kumar

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