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What kind of aneuploid gametes will be generated if meiotic nondisjunction occurs at first division? ('n' represent the haploid number of chromosomes)
Only n+1 and n
Only n - 1 and n
Both n + 1 and n - 1
Either n + 1 or n - 1
Answers (1)
If meiotic nondisjunction occurs at the first division, it can result in the production of two types of aneuploid gametes: gametes with an extra chromosome (n + 1) and gametes with a missing chromosome (n - 1).
During meiosis I, the homologous chromosomes fail to separate properly, leading to an unequal distribution of chromosomes in the resulting daughter cells. If one pair of homologous chromosomes fails to separate, it can result in one daughter cell receiving an extra chromosome (n + 1) and the other daughter cell missing a chromosome (n - 1).
For example, if the haploid number of chromosomes is represented as n, after meiotic nondisjunction at the first division, the possible aneuploid gametes generated are:
n + 1 gamete: This gamete has an extra chromosome compared to the normal haploid set. It occurs when the nondisjunction event results in both homologous chromosomes going to one daughter cell and none to the other.
n - 1 gamete: This gamete is missing one chromosome compared to the normal haploid set. It occurs when the nondisjunction event results in both homologous chromosomes going to one daughter cell, and the other daughter cell ends up without that particular chromosome.
These aneuploid gametes can have implications for genetic disorders or abnormalities if they are involved in fertilization and contribute to the formation of an aneuploid zygote. Hence, the correct answer is option 3.
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