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  • When a certain metallic surface is illuminated with light of wavelength  , the stopping potential is <img a

When a certain metallic surface is illuminated with light of wavelength \lambda , the stopping potential is 3V_{0} . When the same surface is illuminated with light of wavelength 2\lambda , the stopping potential is V_{0} . The threshold wavelength for this surface is-

Option: 1

6\lambda


Option: 2

4\lambda


Option: 3

\frac{\lambda }{4}


Option: 4

None


Answers (1)

best_answer

\begin{aligned} & \mathrm{hv}=\phi_0+\mathrm{eV} \\ & \frac{\mathrm{hc}}{\lambda}=\frac{\mathrm{hc}}{\lambda_0}+\mathrm{e}\left(3 \mathrm{~V}_0\right) \text { and } \frac{\mathrm{hc}}{2 \lambda}=\frac{\mathrm{hc}}{\lambda_0}+\mathrm{eV}_0 \end{aligned}
On solving , \lambda _{0}=4\lambda

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Rishabh

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