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When dioxygen difluoride is made to react with xenon and xenon tetrafluoride respectively, there is liberation of oxygen along with formation of:

Option: 1

\mathrm{XeF}_{4}, \mathrm{XeF}_{2}


Option: 2

\mathrm{XeF}_{2}, \mathrm{XeF}_{6}


Option: 3

\mathrm{XeF}_{6}, \mathrm{XeF}_{6}


Option: 4

None of these.


Answers (1)

best_answer

Xenon has +2  and +6 oxidation state in those two products.

Dioxygen diflouride reacts with xenon to form xenon difluoride and oxygen.

\mathrm{O}_{2} \mathrm{F}_{2}+\mathrm{Xe} \stackrel{391 \mathrm{~K}}{\longrightarrow} \mathrm{XeF}+\mathrm{O}_{2}

Dioxygen diflouride reacts with xenon tetrafluoride to form xenon hexafluoride and oxygen.

\mathrm{O}_{2} \mathrm{F}_{2}+\mathrm{XeF}_{4} \stackrel{143 \mathrm{~K}}{\longrightarrow} \mathrm{XeF}+\mathrm{O}_{2}.

Posted by

SANGALDEEP SINGH

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