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1. A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30° (see Fig. 9.11).


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Given that,
The length of the rope (AC) = 20 m. and \angle ACB =30^o
Let the height of the pole (AB) be h

So, in the right triangle \Delta ABC

By using the Sin rule
\sin \theta = \frac{P}{H} =\frac{AB}{AC}
         \sin 30^o =\frac{h}{20}
         h =10 m.
Hence the height of the pole is 10 m.

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