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1.12  A cubic solid is made of two elements P and Q. Atoms of Q are at the corners of the cube and P at the body-centre. What is the formula of the compound? What are the coordination numbers of P and Q?

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It is given that element Q is at corners of the cube.

So total atoms of element Q per unit cell = 1                                       (8\times\frac{1}{8} = 1)

And it is also given that element P is present at body centre.

So the total number of atoms of element P per unit cell = 1.

Therefore formula of the compound becomes: PQ

It is clear that it is a bcc lattice so coordination number of P and Q is 8.

Posted by

Devendra Khairwa

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