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2.7 Calculate the wavelength, frequency and wavenumber of a light wave whose period is 2.0\times 10^{-10} \ \textup{s}.

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Given frequency, wavelength, and the wave number of a light wave:

Frequency (\nu ) =\frac{1}{Period} = \frac{1}{2.0\times10^{-10}s}= 5\times10^9 s^{-1}

Wavelength (\lambda) = \frac{c}{\nu } = \frac{3.0\times10^8 ms^{-1}}{5\times10^9 s^{-1}} = 6.0\times10^2 m

Wave\ number \left ( \vartheta \right ) = \frac{1}{\lambda} = \frac{1}{6.0\times10^2}m = 16.66\ m^{-1}

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Divya Prakash Singh

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