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  • Find the coordinates of a point on y-axis which are at a distance of 5 root 2 from the point P (3, minus 2, 5).

4.   Find the coordinates of a point on y-axis which are at a distance of 5 \sqrt 2  from the point P (3, –2, 5).

Answers (1)

best_answer

Let the point  Q be (0,y,0)

    Now Given 

The distance of point Q From point P = 5 \sqrt 2

So,

\sqrt{(3-0)^2+(-2-y)^2+(5-0)^2}=5\sqrt{2}

{(3-0)^2+(-2-y)^2+(5-0)^2}=25\times 2

9+(2+y)^2+25=50

(2+y)^2=16

(2+y)=4\:or\:2+y=-4

y=2\:or\:y=-6

The coordinates of the required point is (0,2,0) or (0,-6,0).

Posted by

Pankaj Sanodiya

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