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14.  Given  P(A)=\frac{3}{5}   and    P(B)=\frac{1}{5}.  Find  P(A\hspace{1mm}or\hspace{1mm}B), if  A and  B are mutually exclusive  events.
 

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Given,  P(A)=\frac{3}{5}   and P(B)=\frac{1}{5}

To find : P(A or B) = P(A \cup B)

We know,

 P(A \cup B) = P(A)+ P(B) - P(A \cap B) = P(A)+ P(B)  [Since A and B are mutually exclusive events.]

\implies  P(A \cup B) = \frac{3}{5}+\frac{1}{5} = \frac{4}{5}

Therefore,   P(A \cup B) = \frac{4}{5}

Posted by

HARSH KANKARIA

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