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2.60    The velocity associated with a proton moving in a potential difference of 1000 V is 4.37\times 10^5\ \textup{ms}^{-1} . If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.

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Given a proton is moving with velocity 4.37\times 10^5\ \textup{ms}^{-1}.

And if the hockey ball of mass 0.1kg is also moving with the same velocity, then

According to de-Broglie's equation we have,

\lambda = \frac{h}{mv}

\lambda =\frac{6.626\times10^{-34}Js}{(0.1kg)\times(4.37\times10^5 m/s)}

= 1.516\times10^{-28} m

Posted by

Divya Prakash Singh

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