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  • A projectile is given an initial velocity of (i+2j)m/s where i is along the ground and j is along the vertical. If g=10m/s2, the equation of its trajectory is?

A projectile is given an initial velocity of (i+2j)m/s where i is along the ground and j is along the vertical. If g=10m/s2, the equation of its trajectory is?

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best_answer

The equation of projectile is given by,

y=x\tan \theta-\frac{1}{2}\frac{gx^{2}}{u^{2}\cos ^{2}\theta}\\* \tan \theta=\frac{u_y}{u_x}= \frac{2}{1}= 2\\*

So cos\theta =\frac{1}{\sqrt{5}}

\therefore y= 2x-\frac{1}{2}\frac{10x^{2}}{\left ( 1^{2}+2^{2} \right )\times \frac{1}{5}}

\Rightarrow y= 2x-5x^{2}

Posted by

avinash.dongre

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