# At what point of the parabola x^2 = 9y is the abscissa three times that of ordinate?

$Given:The\;parabola,\;x^2=9y\\*Let\;us\;assume\;the\;point\;be\;(3y_1, y_1)\\*Now\;by\;substituting\;the\;point\;in\;the\;parabola\;we\;get,\\* \Rightarrow (3y_1)^2=9(y_1)\\*\Rightarrow 9(y_1)^2=9y_1\\*\Rightarrow (y_1)^2-y_1=0\\*\Rightarrow y_1(y_1-1)=0\\*\Rightarrow y_1=0\;or\;y_1-1 =0\\*\Rightarrow y_1=0\;or\;y_1=1\\*The\;point\;is\;B(3(1),1)\Rightarrow (3,1)\\*\therefore The\;point\;is\;(3,1).$

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