A wheel of a motor is rotating at 1200 r.p.m. If the radius of the wheel is 35 cm,what linear distance does a point of its rim traverse in 30 second?

Answers (1)

Given,
Radius of the wheel=35 cm
	herefore Circumference of the wheel=2pi r=(2*frac227*35), cm=220, cm
Hence,the linear distance travelled by a point of the rim in one revolution=220 cm.
Now, the speed of the wheel is 1200 revolutions per minute=frac120060 i.e., 20 revolutions per second.
	herefore The number of revolutions in 30 seconds=20*30=600
	herefore The linear distance travelled by a point of the rim in 30 seconds
=(600*220), cm=132000, cm=1.32, km

Most Viewed Questions

Preparation Products

Knockout JEE Main (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-
Buy Now
Knockout JEE Main (Nine Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 13999/- ₹ 12499/-
Buy Now
Knockout NEET (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-
Buy Now
Knockout NEET (Nine Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 13999/- ₹ 12499/-
Buy Now
Test Series JEE Main 2024

Chapter/Subject/Full Mock Tests for JEE Main, Personalized Performance Report, Weakness Sheet, Complete Answer Key,.

₹ 7999/- ₹ 4999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions