# A wheel of a motor is rotating at 1200 r.p.m. If the radius of the wheel is 35 cm,what linear distance does a point of its rim traverse in 30 second?

Given,
$\therefore$ Circumference of the wheel=$2\pi r$=$(2*\frac{22}{7}*35)\, cm=220\, cm$
Hence,the linear distance travelled by a point of the rim in one revolution=220 cm.
Now, the speed of the wheel is 1200 revolutions per minute=$\frac{1200}{60}$ i.e., 20 revolutions per second.
$\therefore$ The number of revolutions in 30 seconds=$20*30=600$
$\therefore$ The linear distance travelled by a point of the rim in 30 seconds
$=(600*220)\, cm=132000\, cm=1.32\, km$

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