Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Find the magnitude of each of the two vectors   and  , having t

Find the magnitude of each of the two vectors \vec{a}  and \vec{b} , having the same magnitude such that the angle between them is 60^{\circ} and their scalar  product is \frac{9}{2}\cdot
.

 

 

 

 
 
 
 
 

Answers (1)

Let \vec{a}  and \vec{b} be 2 such vectors
Now,\vec{a} . \vec{b} = \left | \vec{a} \right |\left | \vec{b} \right |\cos \theta ---(1)
It is given that \vec{a} = \vec{b} ,\theta = 60^{\circ}\; \; and\; \; \vec{a}\cdot \vec{b}= \frac{9}{2}
\therefore Putting there values in equation (1)
\frac{9}{2}=\left | \vec{a} \right |\left | \vec{a} \right |\cos 60^{\circ}
\Rightarrow \frac{9}{2}=\left | \vec{a} \right |^{2}\cdot \frac{1}{2}
\Rightarrow \left | \vec{a} \right |^{2}= 9
\Rightarrow \left | \vec{a} \right |= 3
\therefore \left | \vec{a} \right |= \left | \vec{b} \right |= 3

Posted by

Ravindra Pindel

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Result 2025 LIVE: Class 10th, 12th results by next week; DigiLocker codes, latest updates
anam-khan

Fake notice on CBSE 10th, 12th results 2025 in two-halves viral, board alerts students
anam-khan

CBSE Board Result 2025 LIVE: Class 10th, 12th results on cbse.nic.in soon; pass marks, DigiLocker code

Latest Question