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Find the sum of n terms of series whose nth term is n^2+2^n

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best_answer

Solution: We have,

T_n=n^2+2^n

Let S_n denote the sum of n terms of the series

S_n=sum_k=1^nT_k=sum_k=1^n(k^2+2^k)\ \Rightarrow S_n=n(n+1)(2n+1)/6+(2^1+2^2+2^3+........+2^n)\ \Rightarrow S_n=n(n+1)(2n+1)/6+2(2^n-1)

Posted by

Deependra Verma

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