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If | z-zbar|+|z+zbar| =2 then z lies on.

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Solution:   Let  \z=x+iyRightarrow arz=x-iy

                   left | x 
ight |+left | y 
ight |=1 

                 This  Consists of four line Segments which enclosed enclosed a Square.

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Deependra Verma

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