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  • Suppose a and b satisfy the equation 18a^2+77a+2=0 and 2b^2+77b+18=0 then value of ab+a+1/b is

Suppose a and b satisfy the equation 18a^2+77a+2=0 and 2b^2+77b+18=0 then value of ab+a+1/b is

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Solution:   Note that  2b^2+77b+18=0

              Rightarrow   2+77/b+18(1/b)^2=0

          Thus , a and 1/b  are roots of the equation

          18x^2+77x+2=0   

    herefore      a+1/b=-77/18  and  a/b=2/18=1/9

Now,     ab+a+1 /b=a+1/b+a/b=-77/18+1/9=-25/6

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Deependra Verma

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