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The dipole moment of phenol is smaller than that of methanol. Why?

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The dipole movement is dependent on the polarity of the compound. They are directly proportional, and in the case of phenol, the carbon atom is sp^{2} hybridised, creating an electron-withdrawing effect on the benzene ring. But in methanol, the hybridisation of the carbon is sp^{3}, which results in an electron releasing effect. Due to this scenario, the bond polarity of the C-O bond is more in phenol as compared to methanol.  This directly results in smaller dipole movement in phenol.

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