Home > Radius, velocity and the energy of nth Bohr orbital

Radius, velocity and the energy of nth Bohr orbital - (Concept)

According to Bohr’s theory for hydrogen atom: 

(1) The stationary states for electron are numbered n = 1,2,3.......... These integral numbers are known as Principal quantum numbers.

(2) Bohr radius of nth orbit:

\mathrm{r_{n}= 0.529 \frac{n^{2}}{Z}A^{0}}

where Z is atomic number and radius is calculated by the formula in angstrom (A0)  (1A0=10-10 m)

(3) Velocity of electron in nth orbit:

\mathrm{V_{n}= (2.18\times 10^{6})\frac{Z}{n}\: m/s}

where Z is atomic number

(4) Total energy of electron in nth orbit:

\mathrm{E_{n}= -13.6\: \frac{Z^{2}}{n^{2}}\:eV=-2.18 \times 10^{-18}\frac{Z^2}{n^2}\: J}

where Z is atomic number

Depending upon the units given in the question, the respective formula can be used

(5) Time Period and Frequency of Revolution

        Although the precise equations for time period and frequency of revolution are not required but still it is a good idea to look at the variations of these with the atomic number (Z) and the orbit number (n).

We know that Time period (T) is the time required for one complete revolution and that Frequency (\nu) is inverse of the time period

\therefore T = \frac{distance}{time}= \frac{2 \pi r}{v}

\because \mathrm{r\propto \frac{n^2}{Z} and\: v\propto \frac{Z}{n} }

\therefore T \propto (\frac{n^2}{Z}\times \frac{n}{Z}) \propto (\frac{n^3}{Z^2})

\therefore \nu = (\frac{1}{T}) \propto (\frac{Z^2}{n^3})

It is important that you remember all the above formula and relations

Exam Chapter
JEE MAIN Atomic Structure
Chemistry Part I Textbook for Class XI
Page No. : 48
Line : 5

Bohr’s theory can also be applied to the ions containing only one electron, similar to that present in hydrogen atom.


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