Molecular Orbital Energy Diagrams
The relative energy levels of atomic and molecular orbitals are typically shown in a molecular orbital diagram. As given in the figure below, for a diatomic molecule, the atomic orbitals of one atom are shown on the left, and those of the other atom is shown on the right. Each horizontal line represents one orbital that can hold two electrons. The molecular orbitals formed by the combination of the atomic orbitals are shown in the center. Dashed lines show which of the atomic orbitals combine to form the molecular orbitals. For each pair of atomic orbitals that combine, one lower-energy (bonding) molecular orbital and one higher-energy (antibonding) orbital result. Thus we can see that combining the six 2p atomic orbitals results in three bonding orbitals (one σ and two π) and three antibonding orbitals (one σ* and two π*).
22
molecular orbital diagram
The molecular orbitals are filled in the same manner as atomic orbitals, using the Aufbau principle and Hund’s rule.
Bond Order
The filled molecular orbital diagram shows the number of electrons in both bonding and antibonding molecular orbitals. The net contribution of the electrons to the bond strength of a molecule is identified by determining the bond order that results from the filling of the molecular orbitals by electrons.
The MO technique is more accurate and can handle cases when the Lewis structure method fails, but both methods describe the same phenomenon.
In the molecular orbital model, an electron contributes to a bonding interaction if it occupies a bonding orbital and it contributes to an antibonding interaction if it occupies an antibonding orbital. The bond order is calculated by subtracting the destabilizing (antibonding) electrons from the stabilizing (bonding) electrons. Since a bond consists of two electrons, we divide by two to get the bond order. We can determine bond order with the following equation:
bond order = [(number of bonding electrons)−(number of antibonding electrons)]/2
The order of a covalent bond is a guide to its strength; a bond between two given atoms becomes stronger as the bond order increases. If the distribution of electrons in the molecular orbitals between two atoms is such that the resulting bond would have a bond order of zero, a stable bond does not form.
For example, the bond order of H2 molecule is given as follows:

The molecular orbital energy diagram predicts that H2 will be a stable molecule with lower energy than the separated atoms.
A dihydrogen molecule contains two bonding electrons and no antibonding electrons so we have:
bond order in H2=(2−0)/2=1
Because the bond order for the H–H bond is equal to 1, the bond is a single bond.
Magnetic Moment
The magnetic behaviour of any molecule can be determined from the number of unpaired electrons in the bonding and antibonding orbitals. The molecule is said to be diamagnetic as there is no unpaired electron present in the orbitals and not attracted by the magnet. But if any unpaired electron is present then the molecule is paramagnetic.
For example, O2 molecule has 2 unpaired electrons can be seen from the diagram below:

Therefore, O2 molecule is paramagnetic.
| Exam | Chapter |
| JEE MAIN | Chemical Bonding and Molecular Structure |
When two atoms of chlorine combine to form one molecule of chlorine gas, the energy of the molecule?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Among the following species, the diamagnetic molecule is :
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Among the following molecules/ions, which one is diamagnetic and has the shortest bond length?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
From elementary molecular orbital theory we can give the electronic configuration of the singly positive nitrogen molecule ion N2+ as:
| A. |
|
| B. |
|
| C. |
|
| D. |
|
In oxygen molecule, $\sigma 2 p$ molecular orbital has lower energy than $\pi 2 p$ orbitals. This is due to:
| A. |
|
| B. |
|
| C. |
|
| D. |
|
The $\pi^*$ molecular orbital has ________ nodal planes.
| A. |
|
| B. |
|
| C. |
|
| D. |
|
AX is a covalent diatomic molecule where A and X are second row elements of periodic table. Based on Molecular orbital theory, the bond order of AX is 2.5. The total number of electrons in AX is _______. (Round off to the Nearest Integer).
| A. |
|
| B. |
|
| C. |
|
| D. |
|
In the following, the correct bond order sequence is:
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Which one of the following molecules is paramagnetic ?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Which one of the following species is diamagnetic in nature?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Which one of the following pairs of species have the same bond order?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Which of the following species is not paramagnetic ?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
The bond order in NO is 2.5 while that in NO+ is 3. Which of the following statements is true for these two species?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Which of the following species exhibits the diamagnetic behaviour?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
In which of the following ionization processes, the bond order has increased and the magnetic behaviour has changed?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Using MO theory predict which of the following species has the shortest bond length ?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
In the molecular orbital diagram for the molecular ion, the number of electrons in the
molecular orbital is :
| A. |
|
| B. |
|
| C. |
|
| D. |
|
According to molecular orbital theory, which of the following will not be a viable molecule?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
In which of the following processes, the bond order has increased and paramagnetic character has changed to diamagnetic ?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Two pi and half sigma bonds are present in :
| A. |
|
| B. |
|
| C. |
|
| D. |
|
According to molecular orbital theory, which of the following is true with respect to and
?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
In which of the following ionization processes the bond energy has increased and also the magnetic behaviour has changed from paramagnetic to diamagnetic
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Which of the following molecules/ ions does not contain unpaired electrons?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
The bond order of CO is
| A. |
|
| B. |
|
| C. |
|
| D. |
|
The bond order of NO is
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Among the following, the molecule expected to be stabilized by anion formation is :
| A. |
|
| B. |
|
| C. |
|
| D. |
|
If the magnetic moment of a dioxygen species is 1.73 B.M, it may be:
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Which of the following ion is the smallest in size?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
The magnetic behavior of and
, respectively, are
| A. |
|
| B. |
|
| C. |
|
| D. |
|
According to theory the bond orders for
and
respectively, are
| A. |
|
| B. |
|
| C. |
|
| D. |
|
The bond order and magnetic property of acetylide ion are same as that of:
| A. |
|
| B. |
|
| C. |
|
| D. |
|
In which of the following processes, the bond order increases and paramagnetic character changes to diamagnetic one?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Select the pair having zero unpaired electrons:
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Number of filled $\sigma$ bonding molecular orbitals in anionic Part of $\mathrm{Na}_2 \mathrm{O}_2$ is/are?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
The correct order of energy level is in MOS
| A. |
|
| B. |
|
| C. |
|
| D. |
|
(I) (II)
H –– N - - - N - - - N
In hydrogen azide (above) the bond orders of bonds (I) and (II) are :
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Directions: In the following questions, a statement if Assertion (A) is followed by a statement of reason (R).
Assertion: He2 molecule doesn’t exist.
Reason; It doesn’t has any electron in the bonding molecular orbital.
Mark the correct choice as:
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Directions: In the following questions, a statement if Assertion (A) is followed by a statement of reason (R).
Assertion: C2 molecule is diamagnetic in nature.
Reason: 2s – 2p mixing of orbitals doesn’t take place.
Mark the correct choice as:
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Directions: In the following questions, a statement of Assertion (A) is followed by a statement of reason (R).
Assertion: O2+2 and N2 molecules will have the same bond order.
Reason: 'N' and 'O' are present in the same period.
Mark the correct choice as:
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Which of the following order of energies of molecular orbitals of N2 is correct?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
The correct order of energy level of different orbitals
| A. |
|
| B. |
|
| C. |
|
| D. |
|
When $N_2^{+}$ is formed from $N_2$ bond order ________ and when $\mathrm{O}_2^{+}$ is formed from $O_2$
bond order______
| A. |
|
| B. |
|
| C. |
|
| D. |
|
The bond order in O22– is
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Match List-I with List-II
|
LIST I Tetrahedral Complex
|
LIST II Electronic configuration
|
||
| (A) | $\mathrm{TiCl}_4$ | (I) | $\mathrm{e}^2, \mathrm{t}_2^0$ |
| (B) | $\left[\mathrm{FeO}_4\right]^{2-}$ | (II) | $e^4, t_2^3$ |
| (C) | $\left[\mathrm{FeCl}_4\right]^{-}$ | (III) | $\mathrm{e}^0, \mathrm{t}_2^0$ |
| (D) | $\left[\mathrm{CoCl}_4\right]^{2-}$ | (IV) | $\mathrm{e}^2, \mathrm{t}_2^3$ |
Choose the correct answer from the option given below:
| A. |
|
| B. |
|
| C. |
|
| D. |
|
Which of the following species is paramagnetic?
| A. |
|
| B. |
|
| C. |
|
| D. |
|
We have seen that 1s atomic orbitals on two atoms form two molecular orbitals designated as σ1s and σ*1s.