Comparison of the ionic radii and atomic radii
Variation in a Period
In moving from left to right in a period, the nuclear charge increases and the last electron enters into the same shell, thus the effective nuclear charge increases. Thus in this way, the atomic size decreases in the period.

Variation in a Group
In moving from top to bottom in a group, the number of shells increases due to which the atomic size increases.

The size of the cation is always smaller than its parent atom. In the case of cations, the number of electrons in the ion decrease and the nuclear charge remains the same, thus the effective nuclear charge increases and the size decreases.
The size of the cation decreases as effective nuclear charge increases
M+3 < M+2 < M+ < M
The size of the anion is always greater than its parent atom. In the case of anions, the number of electrons in the ion increase and the nuclear charge remains the same, thus the effective nuclear charge decreases and the size increases.
M-3 > M-2 > M- > M
Atomic Properties
Atomic properties are the physical properties of elements that are related to the atomic number of the elements. These properties can be divided into two categories:
Properties of individual atoms: These are the properties of individual atoms that are directly dependent on their electronic configurations. Some examples include ionisation enthalpy, electron gain enthalpy, screening effect, effective nuclear charge, etc.
Properties of the group of atoms: These are properties of the group of atoms together that are indirectly related to their electronic configurations. Some examples include the melting point, boiling point, the heat of fusion, density, etc.
The Screening effect or Shielding effect
The decrease in the force of attraction between the outer electrons and the nucleus due to the presence of inner electrons is called the screening effect or shielding effect. Actually, these inner electrons generate the repulsion between these inner electrons and the outer electrons due to which the net force of attraction between the nucleus and the outer electrons decreases.
Calculation of the screening effect
For ns or np orbital electrons
All electrons in the (ns, np) group contribute to 0.35 each to the screening effect constant. Except for 1s electrons which contribute by 0.30.
All electrons in (n-1) shell contribute by 0.85 each to the screening effect constant.
All electrons in (n-2) shell or lower contribute by 1.0 each to the screening effect constant.
For d- or f-electrons
All electrons in the (ns, np) group contribute to 0.35 each to the screening effect constant.
All the electrons in groups lower than (nd, nf) contribute by 1.0 each to the screening effect.
Effective Nuclear Charge
Due to the screening effect of the inner or the same shell electrons, the net force of attraction between the nucleus and the outer electrons decreases. This decreased force of attraction is known as effective nuclear charge. It is represented by Z*. Mathematically, it can be formulated as:
Z* = (Z- ), where
is the screening effect constant.
|
II Period |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
|
Z |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
|
𝜎 |
1.7 |
2.05 |
2.40 |
2.75 |
3.10 |
3.45 |
3.80 |
4.15 |
|
Z* |
1.3 |
1.95 |
2.60 |
3.25 |
3.90 |
4.55 |
5.20 |
5.85 |
In a group, the effective nuclear charge almost remains the same.
|
Group I |
Li |
Na |
K |
Rb |
Cs |
|
Z |
3 |
11 |
19 |
37 |
55 |
|
𝜎 |
1.7 |
8.8 |
16.8 |
34.8 |
52.8 |
|
Z* |
1.3 |
2.2 |
2.2 |
2.2 |
2.2 |
Isoelectronic species -
A series of atoms, ions and molecules in which each species contains the same number of electrons but a different nuclear charge.
| Exam | Chapter |
| JEE MAIN | Classification of Elements and Periodic table |
Among the following ionic radii, choose the correct option:
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Which one of the following ions has the highest value of ionic radius?
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Which of the following has the largest ionic radii ?
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The correct order of atomic radii is :
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Effective nuclear charge depends on:
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In comparison to boron, beryllium has:
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The force of attraction between nucleus and electrons increases upon periods because :
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Which of the following orbital has least screening power?
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The order of Ionisation energy of N, O & F is
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Which is the correct order of ionic sizes?
(At. Nos. : Ce = 58, Sn = 50, Yb = 70 and Lu = 71)
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Which of the following fact is/are true for variation of shielding effect in periodic table?
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Which of the following order shows the correct decreasing order of effective nuclear charge?
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These ions O2-, F-, Na+, Mg2+, Al3+ are isoelectronic species. Their ionic radii follow the trend:
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Arrange the following in increasing order of their ionic radii:$\mathrm{Mg}^{2+}, \mathrm{Na}^{+}, \mathrm{F}^{-}, \mathrm{O}^{2-}, \mathrm{N}^{3-}$
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The increasing order of the atomic radii of the following elements is :
(a) (b)
(c)
(d)
(e)
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If the enthalpy of atomisation $B r_{2(l)}$ is $x k J / \mathrm{mol}$ and bond enthalpy for $B r_{2(g)}$ is $y k J / \mathrm{mol}$,, the relation between them :
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Which one is the correct order of the size of the iodine species
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The order of magnitude of ionic radii of ions
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The ionic radius of Na+ ion is 1.02 . The ionic radii (in
) of Mg2+ and Al3+ respectively, are :
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The ionic radii of $\mathrm{O}^{2-}, \mathrm{F}^{-}, \mathrm{Na}^{+}$and $\mathrm{Mg}^{2+}$ are in order:
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The pair in which ions are isoelectronic with is :
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Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): The ionic radii of $\mathrm{O}^{2-}$ and $\mathrm{Mg}^{2+}$ are same.
Reason (R) : Both $\mathrm{O}^{2-}$ and $\mathrm{Mg}^{2+}$ are isoelectronic species
In the light of the above statements, choose the correct answer from the options given below.
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The correct order of increasing ionic radii is
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The ionic radii of are in the order :
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The ionic radii of respectively are
while the covalent radius of
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The correct statement for the ionic radius of from the following is :
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The group having isoelectronic species is :
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The correct sequence which shows decreasing order of the ionic radii of the element is
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For and
the correct order of increasing ionic radii is :
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The isoelectronic set of ions is :
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The correct order of ionic radii for the ions, is :
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Which one of the following has largest ionic radius ?
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The correct increasing order of the ionic radii is
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Which one of the following sets of ions represents a collection of isoelectronic species ?
(Given: Atomic Number : F: 9, Cl: 17)
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Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: Loss of electron from hydrogen atom results in nucleus of ~1.5 × 10–3 pm size.
Reason R: Proton (H+ ) always exists in combined form.
In the light of the above statements, choose the most appropriate answer from the options given below:
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The total number of isoelectronic species from the given set is ________.
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Which is incorrect order of radii?
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Below are two statements: one is labelled as Assertion (A), and the other is labelled as Reason (R).
Assertion (A) : There is a considerable increase in covalent radius from N to P. However from As to Bi only a small increase in covalent radius is observed.
Reason (R) : Covalent and ionic radii in a particular oxidation state increases down the group.
In the light of the above statements, choose the most appropriate answer from the options given below :
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Consider the following elements.

Which of the following is/are true about A',B', C' and D' ?
(A) Order of atomic radii: $\mathrm{B}^{\prime}<\mathrm{A}^{\prime}<$ D $^{\prime}<$ C $^{\prime}$
(B) Order of metallic character: $\mathrm{B}^{\prime}<\mathrm{A}^{\prime}<\mathrm{D}^{\prime}<\mathrm{C}^{\prime}$
(C) Size of the element: $\mathrm{D}^{\prime}<\mathrm{C}^{\prime}<\mathrm{B}^{\prime}<\mathrm{A}^{\prime}$
(D) Order of ionic radii: $\mathrm{B}^{\prime+}<\mathrm{A}^{\prime+}<\mathrm{D}^{\prime+}<\mathrm{C}^{'+}$
Choose the correct answer from the options given below:
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In case of isoelectronic species the size of $\mathrm{F}^{-}, \mathrm{Ne}$ and $\mathrm{Na}^{+}$is affected by:
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The correct order of the atomic radii of C, Cs, Al and S is :
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The statement(s) that are correct about the species $\mathrm{O}^{2-}, \mathrm{F}^{-}, \mathrm{Na}^{+}$and $\mathrm{Mg}^{2+}$.
(A) All are isoelectronic
(B) All have the same nuclear charge
(C) $\mathrm{O}^{2-}$ has the largest ionic radii
(D) $\mathrm{Mg}^{2+}$ has the smallest ionic radii
Choose the most appropriate answer from the options given below :
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If the number of shell of element increases then
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The correct order of screening power of different orbitals
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This property of elements is known as screening power
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On going down to a main subgroup in the periodic table (example Li to Cs in IA or Be to Ba in IIA) the expected trend of change in atomic radius is a:
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The atomic number of s-p-block elements increases than the magnitude of screening constant
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The correct order of electronegativity of the given ions/atoms
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The electron present in $(n-1)$ shell shields the nth shell of an element
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The order of second ionisation energy of the given elements
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The tendency of the electron in the outer most atomic s-orbital to remain unionized or un-shared in compounds, this is
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The ion that is isoelectronic with CO is
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The ionic radii of $\mathrm{Na}^{+}, \mathrm{F}^{-}, \mathrm{O}^{2-}, \mathrm{N}^{3-}$ follow the order
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The isoelectronic pair of ions is
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Among the elements $\mathrm{Li}, N, C$ and Be one with the largest atomic radius is:
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The atomic radii of the alkali metals follow the order
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The atomic radii of the elements across the second period of the periodic table
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Given below are two statements :
Statement (I) : The radii of isoelectronic species increases in the order.
$
\mathrm{Mg}^{2+}<\mathrm{Na}^{+}<\mathrm{F}^{-}<\mathrm{O}^{2-}
$
Statement (II) : The magnitude of electron gain enthalpy of halogen decreases in the order.
$
\mathrm{Cl}>\mathrm{F}>\mathrm{Br}>\mathrm{I}
$
In the light of the above statements, choose the most appropriate answer from the options given below :
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Given below are two statements :
Statement I : The metallic radius of $\mathrm{Na}$ is $1.86 \mathrm{~A}^{\circ}$ and the ionic radius of $\mathrm{Na}^{+}$is lesser than $1.86 \mathrm{~A}^{\circ}$.
Statement II: Ions are always smaller in size than the corresponding elements.
In the light of the above statements, choose the correct answer from the options given below :
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Given two statements below :
Statement I : In $\mathrm{Cl}_2$ molecule the covalent radius is double of the atomic radius of chlorine.
Statement II : Radius of anionic species is always greater than their parent atomic radius.
Choose the most appropriate answer from options given below :
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Ionic radii vary in
(i) inverse proportion to the effective nuclear charge.
(ii) inverse proportion to the square of effective nuclear charge.
(iii) direct proportion to the screening effect.
(iv) direct proportion to the square of screening effect.
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The reason for the small radius of Ga compared to Al is _______.
(i) poor screening effect of d and f orbitals
(ii) increase in nuclear charge
(iii) presence of higher orbitals
(iv) higher atomic number
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The correct order of size of species Fe, Fe2+, Fe3+:
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The ionic radius of Cr is minimum in which of the following compounds?
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O2– is isoelectronic with
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The atomic radii of Li, F, Na and Si follow the order
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The correct sequence for the ions of their radii-
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Which of the follwing relation is the correct about radius:
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Which of the following is the correct order of size of the given species:
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Choose the incorrect trend in the atomic radii ( r ) of the elements :
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The type of oxide formed by the element among $\mathrm{Li}, \mathrm{Na}, \mathrm{Be}, \mathrm{Mg}, \mathrm{B}$ and Al that has the least atomic radius is :
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The atomic radii of a few elements are listed in Table 3.6 . Two trends are obvious. We can explain these trends in terms of nuclear charge and energy level.