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Nature of Roots - (Concept)

Let the quadratic equation is $a x^2+b x+c=0,(a, b, c \in R)$

$D$ (called the discriminant of the equation) $=b^2-4 a d$

The roots of this equation are given by

$x_1=\frac{-b+\sqrt{D}}{2 a}$ and $x_2=\frac{-b-\sqrt{D}}{2 a}$

i) if D < 0, then both roots are non-real (imaginary numbers), and the roots will be conjugate of each other, which means if p + iq is one of  the roots then the other root will be p - iq

ii) If D > 0, then roots will be real and distinc

iii) D = 0, then roots will be real and equal, and they equal$\mathrm{x}_1=\mathrm{x}_2=\frac{-\mathrm{b}}{2 \mathrm{a}}$

Special cases of case ii (D > 0)

i) if a,b,c are rational numbers (Q) and

  If D is a perfect square, then roots are rational

  If D is not a perfect square then roots are irrational (in this case if$p+\sqrt{q}$ is one root of the quadratic equation then another root will be $p-\sqrt{q}$ )

ii) If a = 1 and b and c are integers and  

  If D is a perfect square, then roots are integers

 If D is not a perfect square then roots are non-integer values

Exam Chapter
JEE MAIN Complex numbers and quadratic equations
Algebra (Arihant)
Page No. : 106
Line : 25

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