Browse by Stream
Discuss Doubts
Home
Search for Exam, Articles, Questions
get app
Go To Your Study Dashboard
  1. Home
  2. 1. To at Rot Rat - 1 sin 60° cos 30° + sin 30° cos 60° (1) 2 tan 450+ cos² 30° - sin 60° cas 450 un soc 30 + cosec 30° (v) sin 30° + tan 45° - cosec 60° soo 30° + cos 60° + cot 45° scor 60° + 4 sec 30° - tan* 45° sin 30° + cos² 30°
# Engineering

1. To at Rot Rat - 1 sin 60° cos 30° + sin 30° cos 60° (1) 2 tan 450+ cos² 30° - sin 60° cas 450 un soc 30 + cosec 30° (v) sin 30° + tan 45° - cosec 60° soo 30° + cos 60° + cot 45° scor 60° + 4 sec 30° - tan* 45° sin 30° + cos² 30°

Answers (6)
R Ronak bhalala

Question is not clear. please send again

R Rakesh Raki

question is not clear  send again

R Rakesh Raki

3

N neha

 

Angle in degrees 0 30 45 60 90
sin 0 \frac{1}{2} \frac{1}{\sqrt{2}} \frac{\sqrt{3}}{{2}} 1
cos 1 \frac{\sqrt{3}}{{2}} \frac{1}{\sqrt{2}} \frac{1}{2} 0
tan 0 \frac{1}{{\sqrt{3}}} 1 {{\sqrt{3}}} not defined

\\\mathrm{Cosecant\;\;\;\;\csc t=\frac{\text { hypotenuse }}{\text { opposite }}=\frac{1}{\sin t}}\\\mathrm{Secent\;\;\;\;\sec t=\frac{\text { hypotenuse }}{\text { adjacent }}=\frac{1}{\cos t}}\\\mathrm{Cotangent\;\;\;\;\cot t=\frac{\text { adjacent }}{\text { opposite }}=\frac{1}{\tan t}}

Using the above table and relations the given question can be easily solved. 

 

R Ravindra Pindel

Question is not clear. please send again

R Ravindra Pindel

Question is not clear. please send again

Similar Questions

Exams
Articles
Questions