Get Answers to all your Questions

header-bg qa

A graph between the square of the velocity of a particle and the distance s moved by the particle is shown in the figure. The acceleration of the particle in kilometer per hour square is:



Answers (1)

\begin{aligned} &\mathrm{v}^{2}=2 \mathrm{as}+\mathrm{u}^{2}\\ &y=m x+c\\ &\mathrm{m}=2 \mathrm{a}, \ \ a=\frac{m}{2}\\ &\text {Slope } \mathrm{m} \text { can be calculated as }\\ &\mathrm{m}=\frac{\mathrm{y}_{2}-\mathrm{y}_{1}}{\mathrm{x}_{2}-\mathrm{x}_{1}}=\frac{900-3600}{0.6-0}\\ &=-\frac{2700}{0.6}\\ &\therefore \mathrm{a}=-\frac{\mathrm{m}}{2}=-\frac{4500}{2}=-2250 \mathrm{km} / \mathrm{hr}^{2} \end{aligned}

Posted by


View full answer