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  • 2 moles of chlorine gas occupies a volume of 800 ml at 300 K and 50 bar pressure. Calculate the compressibility factor of the gas.Option: 1 0.8</

2 moles of chlorine gas occupies a volume of 800 ml at 300 K and 50 bar pressure. Calculate the compressibility factor of the gas.

Option: 1

0.8


Option: 2

0.87


Option: 3

0.97


Option: 4

0.89


Answers (1)

best_answer

We have given:
V = 800 ml or 0.80 L
T = 300 K
P = 50 bar
For the compressibility factor, we know:

Z=\frac{PV}{nRT}

Z=\frac{0.8\times 50}{2\times 0.083 \times 300}=0.80

Hence, the option number (1) is correct.

 

Posted by

Gautam harsolia

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