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  • 3g of acetic acid is added to 250 mL of 0.1M HCl and the solution made up to 500 mL. To 20 mL of this solution  mL. of 5 M NaOH is added. The

3g of acetic acid is added to 250 mL of 0.1M HCl and the solution made up to 500 mL. To 20 mL of this solution \frac{1}{2} mL. of 5 M NaOH is added. The pH of the solution is_______. [ Given: pKa of acetic acid = 4.75, molar mass of acertic acid = 60 g/mol, log3 = 0.4771] Neglect any chnages in volume.
 

Answers (1)

best_answer

Given,

m mole of acetic acid in 20 mL = 2
m mole of HCl in 20 mL = 1
m mole of NaOH = 2.5

\mathrm{CH_{3}COOH\: +\: NaOH(remaining)\: \rightarrow \: CH_{3}COONa\: +\:water}
          2                              3/2                                      0                                 0
         0.5                             0                                       3/2            

\mathrm{pH\: =\: pK_{a}\: +\: log\frac{\frac{3}{2}}{2}}

pH = 4.74 + log 3

pH = 4.74 + 0.48 = 5.22

Thus, the correct answer is 5.22

Hence, the option number (1) is correct.

Posted by

Kuldeep Maurya

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