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5v of stopping potential needed for the photoelectrons emitted out of a surface of work function 2.2ev by the radiation of wavelength

Option: 1

1719A^{\circ}

 

 

 


Option: 2

8.3444A^{\circ}


Option: 3

861A^{\circ}


Option: 4

3000A^{\circ}


Answers (1)

best_answer

As we learned

 

Stopping Potential /Cut-off Potential -

It is defined as the potential necessary to stop any electron from reaching the other side.

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h\nu = 5ev+2.2ev=7.2ev

7.2=\frac{hc}{\lambda A^{\circ}}\Rightarrow \lambda= \frac{hc}{7.2(ev)}=\frac{12400}{7.2}A^{\circ}

\lambda =1719A^{\circ}

Posted by

HARSH KANKARIA

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