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8 identical cells with emf 2V and internal resistance 1\Omega are connected in a row and 16 such rows are connected together in parallel . Then the current passing through of an external resistance 4\Omega is

Option: 1

\frac{23}{9}A


Option: 2

\frac{32}{9}A


Option: 3

\frac{16}{9}A


Option: 4

\frac{64}{9}A


Answers (1)

best_answer

As we learnt

Main current flowing through the load -

 

i= \frac{nE}{R+ \frac{nr}{m}}= \frac{mnE}{mR+nr}

-

i=\frac{mnE}{mR+nr}=\frac{8*16*2}{8*1+16*4}= \frac{256}{72}= \frac{32}{9}A

Posted by

Gautam harsolia

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