Suppose the velocity along the x-axis is $u_x$ and distance travelled in the x-direction is 18 m in 4 min.
therefore,
$u_x$ = distance / time
= 18 / 2
= 9 m/s

and acceleration along y-axis is $-10\ m/s^2$
So, $s = u_yt+\frac{1}{2}at^2$

By substituting the values in the above equation, we get
$u_y = 12\ m/s^2$

Therefore, resultant = $\sqrt{u_x^2+u_y^2+2u_xu_y\cos \theta}$
By putting the values in the above equation, we get
$u = 15\ m/s$

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