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  • A body of mass 1Kg lies on smooth inclined plane. A force F=10m is applied horizontally on the block as shown. The magnitude of normal reaction by inclined plane on the block is <img alt=

A body of mass 1Kg lies on smooth inclined plane. A force F=10m is applied horizontally on the block as shown. The magnitude of normal reaction by inclined plane on the block is

Option: 1

10\sqrt2N


Option: 2

\frac{10}{\sqrt2}N


Option: 3

10N


Option: 4

None of these


Answers (1)

best_answer

\\ \text{Free body diagram of given system : }

       

         

\\ \text{Equation of 1 kg block Perpendicular to inclined plane : }

 

N=10\sin 45^{\circ}+mg\cos45^{\circ}

\\ N=\frac{10}{\sqrt2}+\frac{10}{\sqrt2}= 10\sqrt2N

 

Posted by

Suraj Bhandari

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