A car is travelling due north at 20 m/s turns west and travels at the same speed . The change in its velocity be

Answers (1)

Let the velocity vectors be $\mathrm{v}_{1}=20 \mathrm{m} / \mathrm{s}$  due North and $\mathrm{v}_{2}=20 \mathrm{m} / \mathrm{s}$  due East.
Change in velocity $=\mathrm{v}_{2}-\mathrm{v}_{1}$ 
$\left|v_{2}-v_{1}\right|=\sqrt{\left\{v_{1}^{2}+\left(-v_{2}\right)^{2}\right\}}=\sqrt{\left\{20^{2}+20^{2}\right\}}=20 \sqrt{2} \mathrm{m} / \mathrm{s}$ 
Now $v_{2}-v_{1}=20 \sqrt{2} m / s$  due to south west.

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