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A car moves on a concave bridge of radius R then the maximum reaction force on the car will be:

[ let the mass of the car be m]


Option: 1


Option: 2


Option: 3

mg - \frac{mv^{2}}{R}

Option: 4

mg + \frac{mv^{2}}{R}

Answers (1)






As we learn

Reaction of Road on Car -

Centripetal force = R-mg\ cos\theta=\frac{mv^{2}}{r}

Reaction R =mg\ cos\theta+\frac{mv^{2}}{r}

R = reaction


r = radius

- wherein

It is a case when car moves on a concave bridge.


 maximum reactor will be at lowest point of bridge ,so

N = mg + \frac{mv^{2}}{R}


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